MATH SOLVE

5 months ago

Q:
# 30 points for full answer.1. Solve the equation: (x-4)^2-28=8 Show your work. Don’t forget that you will get two answers. Use the square root property to solve2. This is Josh’s solution for the equation :Step 1: x² - 6x – 7 = 0Step 2: x² - 6x = 7Step 3: x² - 6x + 9 = 7 + 9Step 4: (x – 3)² = 16Step 5: x – 3 = 16Step 6: x = 19Step 7: x – 3 = -16Step 8: x = -13Where did Josh make his mistake? What are the solutions to this equation? Show all of your work. This problem is solved using completing the square.The mistake was in step _____________. Here is how to correctly solve the equation:

Accepted Solution

A:

1. (x-4)^2-28 = 8

(x-4)^2 = 36, we square both sides and get;

x-4 = 6, x = 10

and

x-4 = -6, x = -2

2. The mistake was in step 5.

x² - 6x – 7 = 0; x² - 6x = 7; x² - 6x + 9 = 7 + 9; (x – 3)² = 16

x – 3 = 4; x = 7

x – 3 = -4; x = -1

---

Hope this helps!

(x-4)^2 = 36, we square both sides and get;

x-4 = 6, x = 10

and

x-4 = -6, x = -2

2. The mistake was in step 5.

x² - 6x – 7 = 0; x² - 6x = 7; x² - 6x + 9 = 7 + 9; (x – 3)² = 16

x – 3 = 4; x = 7

x – 3 = -4; x = -1

---

Hope this helps!